Denver Broncos quarterback Jay Cutler will be named AFC Offensive Player of the Week for games played during the 10th week (Nov. 6-10) of the 2008 season, the National Football League informed the Broncos on Tuesday.

Cutler's selection as AFC Offensive Player of the Week is the first such award of his three-year NFL career. It marks his second league-issued honor this season-He was named AFC Offensive Player of the Month for September.

During the Broncos' 34-30 win at Cleveland on Thursday night, Cutler tied for the third-highest single-game passing yardage total (447) in Denver history and registered his fifth-career fourth-quarter comeback. He helped Denver overcome a 23-13 deficit in the fourth quarter and finished the game completing 24-of-42 passes for 447 yards with three touchdowns and one interception for a 107.9 passer rating.

Cutler, who accounted for 476 yards of offense (447 pass, 29 rush) against Cleveland, also helped the Broncos tie for their second-highest single-game yardage total (564) in club history.

In nine games this season, Cutler has totaled an AFC-best 2,616 passing yards that rank third in the NFL. His five 300-yard passing games this year tie Denver's single-season franchise record and lead his conference while tying for second in the league.

Cutler is the second Bronco to be named AFC Offensive Player of the Week this year with wide receiver Brandon Marshall earning that honor for his Week 2 performance against San Diego. He is the first Denver quarterback to receive the award since 2005 (Jake Plummer, Week 8 vs. Philadelphia).

His selection marks the 43rd time a Broncos player has received AFC Offensive Player of the Week honors since the award was initiated by the NFL in 1984.